A100 g ball moving to the right at 4.0 m/s collides head-on with a 200 g ball that is moving to the left at 3.0 m/s.

if the collision is perfectly elastic, what are the speeds of each ball after the collision?

The final speed of the 100-g ball is about 5.3 m/s to the left

The final speed of the 200-g ball is about 1.7 m/s to the right

Newton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.

F = Force ( Newton )

m = Object's Mass ( kg )

a = Acceleration ( m )

Let us now tackle the problem !

Given:

mass of ball 1 = m₁ = 100 g

initial velocity of ball 1 = u₁ = 4.0 m/s

mass of ball 2 = m₂ = 200 g

initial velocity of ball 2 = u₂ = -3.0 m/s

Asked:

final velocity of ball 1 = v₁ = ?

final velocity of ball 2 = v₂ = ?

Solution:

Firstly , we will use Conservation of Momentum Law as follows:

→ Equation 1

If the collision is perfectly elastic , then:

→ Equation 2

Let's solve the two Equations above:

(Equation 1) + (Equation 2) ↓

Grade: High School

Subject: Physics

Chapter: Dynamics

Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant

probably not the "magnets"in the magnet, so to speak, are thought to be electrons orbiting in shells. vurrent loops two sides to the loop

the chart show the masses and velocities of two colliding objects that stick together after a collision.

according to the law of conservation of momentum, the momentum of the object after the collision is  

answer

1,500

kg • m/s.