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Physics, 18.09.2019 16:30 SmokeyRN

An object is launched at 20 m/s from a height of 65 m. the equation for the height (h) in terms of time (t) is given by h(t) = -4.9t² + 20t + 65. what is the object's maximum height? the numeric answer only, rounded to the nearest meter.

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An object is launched at 20 m/s from a height of 65 m. the equation for the height (h) in terms of t...
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