A 1.6 kg chicken is blown into a wall by a strong gust of wind, and held there as shown in Figure 2.13. If the maximum coefficient of friction between the chicken and the wall is mu max =0.25 , what minimum force must the gust of wind be applying to the chicken?

Friction force required to hold the chicken;

=>By Ff = µs x N

=>Ff = mg = 0.25 x N

=>1.6 x 9.8 = 0.25 x N

=>N = 62.72 Newton

Explanation:

this one:

as we gain mass the force of gravity on us increases.

pls mark me as the ! : d

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s