A person starts running from 2 m/s to 6 m/s in 2 seconds. Calculate the person's acceleration.
Var
Variables:
Solve:
F
Formula:

2 m/s²

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 2 m/s

Final velocity (v) = 6 m/s

Time (t) = 2 s

Acceleration (a) =?

The acceleration of the person can be obtained as follow:

v = u + at

6 = 2 + (a×2)

6 = 2 + 2a

Collect like terms

6 – 2 = 2a

4 = 2a

Divide both side by 2

a = 4 / 2

a = 2 m/s²

Therefore, the acceleration of the person is 2 m/s²

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pe = weightxheight = 2000x1000=2,000,000joules