Abaseball is thrown upward from a height of 2 meters with an intial velocity of 10 meters per second . determine its maximum height, using a(t)=-9.8 meters per second as acceleration due to gravity.

The equation to be used for this would be as follows:

h(x) = -9.8x^2 + 10x + 2

We need to find for the axis of symmetry for the time it takes to reach the maximum height and is expressed as:

x = -b/(2a)
x = -10/2(-9.8)
x = 0.51 seconds is the time it takes to reach the max. height

h(x) = -9.8x^2 + 10x + 2
h(x) = -9.8x0.51^2 + 10x0.51 + 2
h(x) = 4.55 m

the simple machine has three main features. they are:

loadfulcrumeffort

fulcrum is the center point or pivot point of the machine. effort is input force/ applied force. load is external force/ output.

the keisha 's machine labels are

x : load

y: fulcrum

z: lever

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