Amotor that uses electrical energy at a rate of 1.5 kw is connected to a hydraulic lift that is used to lift a 1300 kg car to a height of 1.8 m in 24 s at a constant speed. find the efficiency of the system consisting of the motor and the lift.

Efficiency is a measure of how much work or energy is conserved in a process. The efficiency is the energy output, divided by the energy input, and expressed as a percentage. It is calculated as:

efficiency (%) = (useful energy out ÷ total energy in) x 100
efficiency (%) = (((1300x9.8x1.8)/24x1000 )÷ 1.5 kW ) x 100
efficiency (%) = 63.7%

Hope this answers the question. Have a nice day.