The volume of an object as a function of time calculated by V=At^3+B/t, where t is time measured in seconds and V is in cubic meters. Determine the dimension of the constants A and B

A = L^3 T^-3  ,  B = L^3 T

Explanation:

Given: volume ( V )  = At^3 + B/t   ( 1 )

dimension of volume = L^3

and the Dimension of time = T

back to equation ( 1 )

L^3 = A * T^3   ( 2 )

also L^3 = B/T ( 3 )

from equation ( 2 )

A = L^3 T^-3

from equation ( 3 )

B = L^3 T

The dimensions of the constants A and B

A = L^3 T^-3  ,  B = L^3 T

higher potential

explanation:

because it is in a high speed so it must move into a of high potential