Kelvin is teeing off on a 190.0 m long par 3 hole. The ball leaves with a velocity of 50.0 m/s at 37.0o to the horizontal. Assuming that Kelvin hits the ball on a direct path to the hole, how far from the hole will the ball land (no bounces or rolls)?

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Answerthe force between the charges will be  f/9 (one-ninth of force f)explanationcoulomb's law relates the magnitudes  two point charges q₁ and q₂, the distance, r, between the charges, and the electrostatic force, f, between the two charges:     k represents coulomb's constant, k = 8.99×10⁹ n·m²/c².note that if we have r = 3r, then