Physics, 08.04.2021 14:00 suselygonza

A 1-kg ball is 12 m above the ground, with an initial velocity = 0 m/s. Use the following formulas
[ KE = 1/2 xm x V2]
[P. E = mxgxh] . g =9.8 m/s2
[ Mechanical energy = K. E + P. E]

A 1-kg ball is 12 m above the ground, with an initial velocity = 0 m/s.

Use the following formula

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A 1-kg ball is 12 m above the ground, with an initial velocity = 0 m/s. Use the following formulas<...

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