If a current of 1.10 A flows through a 7.00 Ω resistor of length 3.00 m, what is the electric field strength inside the resistor?

the electric field strength inside the resistor is 2.57 V/m

Explanation:

Given;

current flowing through the wire, I = 1.10 A

resistance of the wire, R = 7.00 Ω

length of the wire, L = 3.00 m

The emf created inside the resistor is calculated as;

V = IR

V = 1.10 x 7

V = 7.7 V

The electric field strength inside the resistor is calculated as;

E = V/L

E = 7.7 / 3

E = 2.57 V/m

Therefore, the electric field strength inside the resistor is 2.57 V/m

a small object of mass 3.66 g and charge -17.6 µc is suspended motionless above the ground when immersed in a uniform electric field perpendicular to the ground. what are the magnitude and direction of the electric field?

force is based upon mass and acceleration.the statement is not always true.

it can be explained from newton's second law of motion.

as per newton's second law of motion the rate of change of momentum is directly proportional to the applied force and takes place along the direction of force.

mathematically it can be written as -

                                              ⇒      

here   k is the proportionality constant whose value is 1.

                                                            [a is the acceleration=dv/dt]

hence we see that force not only depends on mass and acceleration but also on velocity and rate of change of mass. force f will depend on mass and acceleration only when mass is constant.

hence the statement that force is based upon mass and acceleration is false.