Someone. problem:

starting with an initial speed of 5.00 m/s at a height of h = 0.260 m, the m1 = 1.55 kg ball swings downward and strikes the m2 = 4.50 kg ball that is at rest, as the drawing shows.

(a) using the principle of conservation of mechanical energy, find the speed of the 1.55-kg ball just before impact.
(b) assuming that the collision is elastic, find the velocities (magnitude and direction) of both balls just after the collision.
(c) how high does each ball swing after the collision, ignoring air resistance?

Part a)

Part b)

Part c)

Explanation:

Part a)

As we know by energy conservation law

initial kinetic energy + initial potential energy = final kinetic energy + final potential energy

So here we know that

now we have

Part b)

As we know that collision is perfectly elastic collision

so we will have

also we know for elastic collision

Part c)

Now the height of each ball is given by

a small object of mass 3.66 g and charge -17.6 µc is suspended motionless above the ground when immersed in a uniform electric field perpendicular to the ground. what are the magnitude and direction of the electric field?

from

explanation:

wind is defined by the direction it blows from.   for example, a wind blowing from north to south is called a northerly wind.