A Ferris wheel with a diameter of 35 m starts from rest and achieves its maximum operational tangential speed of 2.3 m/s in a time of 15 s. what is the magnitude of the wheels angular acceleration? b. what is the magnitude of the tangential acceleration after the maximum operational speed is reached?​

8.8e-3 rad/s², 0.0 m/s²

Explanation:

R = 35 / 2 = 17.5 m

a = 2.3 m/s / 15 s = 0.1533333... m/s²

α = a/R = 0.1533333/17.5 = 0.0087619... ≈ 8.8e-3 rad/s² ◄(a)

at maximum speed, no more acceleration in either tangential or angular

α = a = 0.0 rad/s² or m/s² ◄(b)

c.the charges if the proton and electron and gravity

the temperature and the pressure affect solubility. temperature affects by changing the properties of the solvent. the increase in pressure increases solubility, the decrease in pressure decreases solubility.