Acomputer base unit of mass 7.5 kg is dragged along a smooth desk. if the normal contact force is 23n and the tension in the arm of the person dragging it acts at 23 degrees to the horizontal, then what is the total tension in the person's arms?

Total tension in the person's arm = 58.82 N

Explanation:

Normal Contact Force: Normal contact force is the vertical  component of the contact force that is perpendicular to the surface that an object makes contact with.

As shown in fig.1 in the diagram on the attached file below.

The Normal contact force (R) = Tsinθ = The vertical component of T

Where T = Total tension in the person's arm (N), θ = angle of inclination to the horizontal.

∴ R = Tsinθ

T = R/sinθ where R= 23N, θ =23°

T = 23/sin23° = 23/0.391

T = 58.82 N

∴ Total tension in the person's arm = 58.52 N

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