Calculate the quantity of work, in joules, associated with the compression of a gas from 5.64 l to 3.35 l by a constant pressure of 1.21 atm

In thermodynamics, work performed by a system is the energy transferred by the system to its surroundings. It is calculated by the integral of pressure and volume of the system. At constant pressure, the expression for work would be as follows:

W = P(V2-V1)
W = 1.21(3.35 -5.64) = -2.77 L-atm
W = -2.77 (101.33) = -280.78 J

The objects do not reach terminal velocity         there is not enough time from the time the object falls from when it hits the ground to achieve terminal velocity. an object must be placed higher to achieve terminal velocity in order to be in free fall.