A horizontal 2.00\ m2.00 m long, 5.00\ kg5.00 kg uniform beam that lies along the east-west direction is acted on by two forces. At the east end of the beam, a 200\ N200 N forces pushes downward. At the west end of the beam, a 200\ N200 N force pushed upward. What is the angular acceleration of the beam

Explanation:

Given

Length of beam

mass of beam

Two forces of equal intensity acted in the opposite direction, therefore, they create a torque of magnitude

Also, the beam starts rotating about its center

So, the moment of inertia of the beam is

Torque is the product of moment of inertia and angular acceleration

multiple

d

explanation:

v=uf/(u-f)

= 5.10/(5-10) convex lens has positive focal length

=50/-5

=-10 cm (formed at other side)