lodine-131 has a half life of about 8 days. If you had 60 grams of , how much would remain after 24 days?

7.5 grams

Explanation:

From the question,

(R/R')ᵇ = 2ᵃ Equation 1

Where b = half life, R = Original mass of iodine, R' = Remaining mass of Iodine after disintegration, a = Total time taken.

⇒ R/R' = 2ᵃ/ᵇ Equation 2

Given: R = 60 grams, a = 24 days, b = 4 days

Substitute these values into equation 2

60/R' = 2²⁴/⁸

60/R' = 2³

R' = 60/2³

R' = 60/8

R' = 7.5 grams

yeet youwelcome broo

0.3x0.21x0.08kg=mass 1 sheet

mass 500 = 500xmass 1

volume pile = 0.3x0.2x0.048

density=mass/volume= 500xmass 1/0.3x0.2x0.048

v patient student