what is the power output needed from a motor to lift in the absence of friction a mass of 1.5 ×10⁴ kg 25 m in 6.0 s at constant speed​

the power output needed is  61.25 × 10⁴

Explanation:

The computation of the power output needed is shown below;

Given that

m =  1.5 ×10⁴ kg

v = 25m  ÷ 6.0 s

And g = 9.8 m/sec^2

Now based on the above information

p = f × v

= mg × v

= 1.5 ×10⁴ × 9.8 × 25 ÷ 6

= 61.25 × 10⁴

Hence, the power output needed is  61.25 × 10⁴

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees. 

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