Tarzan, whose mass is 100 kg, is hanging at rest from a tree limb. Then he lets go and falls to the ground. Just before he lets go, his center of mass is at a height 2.9 m above the ground and the bottom of his dangling feet are at a height 2.1 above the ground. When he first hits the ground he has dropped a distance 2.1, so his center of mass is (2.9-2.1) above the ground. Then his knees bend and he ends up at rest in a crouched position with his center of mass a height 0.5 above the ground. Consider the point particle system. What is the speed v at the instant just before Tarzan's feet touch the ground?

Explanation:

v = Final velocity

u = Initial velocity = 0

s = Displacement of Tarzan's feet = 2.1 m

a = g = Acceleration due to gravity =

From the kinematic equations we get

At the instant just before Tarzan's feet touch the ground the velocity of his feet are .

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explanation:

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dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.