A spanner of length 9.1 cm is used to turn a nut by applying a force of 11 N with a torque of 0.56 Nm. At what angle should the force be applied to the handle? (Show Work)

FIRST CHANGE CM INTO M

 ⊥ Distance = 10cm = 10/100 = 1/10 m Force applied on spanner 5 N ∴ Moment of force = F ×⊥ distance = 5 × 1/10 = 0.5 nm.

Explanation:

explanation:

newton's third law, for every action there is an equal and opposite reaction.

he made 11 calls in one day