2. A train undergoing uniformly accelerated motion changed its of 36m/s in 12 sec. Calculate:
A. The acceleration of the train
B. The time to attain a velocity of 24m/s
C. The velocity after 10 sec.
D. The average velocity after 6Sec.
E. The distance covered after 8 sec.
F. The time required to cover 27m
G. The distance where its velocity is 16 m/s
10 m/s2
Steps are mandatory

Hey hope you get the answer but i suck at math sorry : (

Ohm's law tells you that i = v/r where v is equivalent voltage and r is equivalent resistance of the circuit
since all circuits have the same voltage, your question is really asking which circuit has the lowest total resistance, since the lower the resistance, the higher the current
circuit a has a resistance of 5 ohms; circuit c is in series so has a resistance of 10 ohms; circuit b is in parallel and therefore has a resistance of 2.5 ohms (review your notes on adding resistances in parallel and series); therefore b has the highest current

Answerthe force between the charges will be  f/9 (one-ninth of force f)explanationcoulomb's law relates the magnitudes  two point charges q₁ and q₂, the distance, r, between the charges, and the electrostatic force, f, between the two charges:     k represents coulomb's constant, k = 8.99×10⁹ n·m²/c².note that if we have r = 3r, then