If the maximum moment of force on a door is 10 Nm by an applied force of 2.25 N, then the distance of handle

d = 4.44 m

Explanation:

Given that,

The moment of force on a door = 10 N-m

The applied force, F = 2.25 N

We need to find the distance of the handle. The moment of force is given by :

Where

r is the distance of the handle.

So, the required distance is equal to 4.44 m.

305.7

explanation:

density =m/v

density =917/3.00

density = 305.

approximately = 305.7

in four significant figures