A 10 ohms resistor, 10 mh inductor, and 10micro farad capacitor are connected in series with a 10khz voltage source. The rms current through the circuit is 0.20A. Find the rms voltage drop across each of the three elements

126 V

Explanation:

The computation of the rms voltage is shown below:

=  I × R

=(.2) × (10)

= 2 V voltage drop across capacitor

= I × 1 ÷ (?C)

= I ÷ (2 × pi × f × C)

= (.2) ÷ (2 × pi × 10,000 × 10 × 10^-6)

= .318 V voltage drop across inductor

= I × ?L

= I × 2 × pi × f × L

= .2 × 2 × pi × 10,000 × .010

= 126 V

u=13

v=30

s/t=u+1\2at

=13+431/2

=13+265.5

=278.5

terd muffin is the correct answer