If you use a lever to lift a boulder 0.25m, while applying 350 N on the lever which moves 1.5 m down on your side. What is the weight of the boulder? (F1d1 = F2d2) 87.5 N 131 N 525 N 2100 N

2100 N

Explanation:

From the question,

Using the formula

F₁d₁ = F₂d₂ Equation 1

Where F₁ = Weight of the Boulder, d₁ = distance moved by the Boulder, F₂ = Force applied on the lever, d₂ = distance moved by the lever.

make F₁ the subject of the equation

F₁ = F₂d₂/d₁ Equation 2

Given: F₂ = 350 N, d₁ = 0.25 m, d₂ = 1.5 m

Substitute these values into equation 2

F₁ = 350(1.5)/0.25

F₁ = 2100 N

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