A ball rolls off the edge of a balcony at 10 m/s. What is its speed after 1 s in the air

V = 19.8 m/s

Explanation:

Given the following data:

Initial velocity = 10m/s

Time, t = 1 secs

We know that acceleration due to gravity is equal to 9.8m/s

To find the final velocity, we would use the first equation of motion;

Where;

V is the final velocity.

U is the initial velocity.

a is the acceleration.

t is the time measured in seconds.

Substituting into the formula, we have;

V = 10 + 9.8*1

V = 10 + 9.8

V = 19.8 m/s

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