If a spring has an elastic potential energy of 60 J and a displacement of 4 m , what is the spring constant of the spring?

7.5 N/m

Explanation:

Potential energy of a spring can be calculated using below formula

Potential energy= 1/2kx^2

potential energy = 60 J

X= displacement = 4 m

K= spring constant=?

Substitute the values we have

60= 1/2 × K × 4^2

60= 1/2 × K × 16

60= K × 8

K= 7.5 N/m

Hence, the spring constant of the spring is 7.5 N/m

its a 5.5 n

glad that

when jerome paddle in flowing river towards east the net speed of jerome will increase

so the net speed of jerome will be given as

now the speed of paul will be same as it is given as he is running on the ground

so

so here we can say since the speed of jerome is more so he will win the race

now as we know the distance so the time difference is given as

so jerome will reach first and the time difference will be 203.55 s or 3.4 min