Aparticle moves along the x-axis so that at time t > (or equal to) 0 its position is given by x(t)=2t^3 - 21t^2 + 72t-53. at what time t is the particle at rest?

A particle will be rest firstly at t = 3 sec and again t = 4 sec.

Explanation:

Given that,

The equation of position,

We need to calculate the velocity

On differentiating equation of position

A particle is at rest when the velocity equal to zero.

So,

After solution,

,

Hence, A particle will be rest firstly at t = 3 sec and again t = 4 sec.

f=ma a/f/m a= 480/60 a = 8m/s/s that is quick wow

answerscientific theory;