What is the elastic potential energy of a spring with a 80 N/m spring constant that has been moved 0.6 m from equilibrium?

1. F = 0.25N

2. k = 80 N/m

3. x = 0.2m

4. a = 1m/s²

5. x = 42.6m

Explanation:

1. F = kx

 F = 2.5 X 0.1

 F = 0.25N

2. x = 0.25m

  F = 20 N

  F = kx

  20 = k X 0.25

  k = 80 N/m

3. k = 3500 N/m

  F = 700 N

  x = ?

  700 = 3500 x

  x = 0.2m

4. m = 20kg

  k = 244 N/m

  x = 0.1m

  F = 20N

  a = ?

  F = ma

  20 = 20 a

   a = 1m/s²

5. k = 2.3 N/m

  m = 10kg

  x = ?

  F = kx

  10 X 9.8 = 2.3 x

   x = 42.6m

wavelength divides in half and speed stays the same.