A pelican flying along a horizontal path drops a fish from a height of 7.0 m. The fish travels 8.0 m horizontally before
it hits the water below. What is the pelican's speed?

time for fish to fall 5.4 m = √2d/g = √(2)(5.4)/9.81 = √1.100917 = 1.0492 s

pelican's initial speed = horizontal fish speed = 8.0/1.0492 = 7.6 m/s ANS a)

time for fish to fall 2.7 m = √2d/g = √0.55046 = 0.7419 s

fish travels a distance = speed x time =  (7.6)(0.7419) = 5.6 m ANS b)

depends on what you mean by "group." for order, it would be coleoptera (beetles). for class, it would be insecta (insects). for phylum, it would be the arthropoda (animals with jointed exoskeletons).

explanation:

find the sum of the two horizontal vectors and the sum of the two vertical vectors

isoceles right angled triangle