When an object is placed 15 cm from "
a concave mirror, a real image magnified
3 times is formed - Find
a) the focal length of the mirror
b) where the object must be placed to
give a virtual image 3 times the height
of the object

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Focal length(f)= -15 cm, magnification= -3 (image is real). So, -v/u=-3 ; or v=3u {v=image distance and u=object distance}. Using mirror formula,

1/f= 1/v + 1/u

-1/15 = 1/3u + 1/u

4/3u = -1/15

u= -20 cm

v =3u= 3×(-20)= -60 cm

So object is 20 cm and image is 60 cm in front of the mirror.

Explanation:

e

explanation:

there is no change in the electric potential energy as it is in rest on both conditions.