The pilot directs the aircraft to fly due north at 600km/h. A side-wind blows at 100km/h towards the east. What will be the aircraft's resultant velocity? (Give both its
speed and direction)

678.2 km/h and 80.54° north of east

Explanation:

From the question,

Using pythagoras theorem,

a² = b²+c² Equation 1

Where a = resultant velocity

Given: b = 600 km/h, c = 100 km/h

Substitute these values into equation 1

R² = 600²+100²

R² = 360000+10000

R² = 460000

R  = √460000

R = 678.2 km/h.

And the direction is

tanθ = 600/100

tanθ = 6

tanθ = 6

θ = tan⁻¹(6)

θ = 80.54°.

Hence the resultant velocity of the aircraft is 678.2 km/h and 80.54° north of east

answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg