The figure below shows the head of a patient being fixed to a Russell Traction System, where the patient is laying down on his back on a bed that is inclined by 20o with the horizontal as shown. The static frictional force between the patient and the bed is 190N and the coefficient of static friction is 0.4. (a) Find the weight of the patient.
(b) Find the minimum balancing mass, M that stretches the patient from upwards

Since you have not included the experiment situation and the data, of course, i can not give you specific details about it. but i can you with this question.1) i will assume that the motion is projectile (parabolic) motion.2) yes, the horizontal distance depends on the horizontal velocity as, naming vx the horizontal velocity and t the time, it is: x = vx × t3) now, observe that the flight time depends on the vertical velocity as, naming voy the initial vertical velocity, t the time and y the vertical distance before reaching the ground: y = yo + voy×t - gt² / 2.the higher the initial vertical velocity (voy) the longer the object will be flying and so t will be higher in the equation for the horizontal distance.that explains the relationship between the horizontal distance and the horizontal velocity.