A stone of mass 0.2kg is thrown vertically upwards from the ground with a velocity of 20m/s. Find the maximum height attained by the stone

20.4 m

Explanation: speed v upward is v = vo -gt.

When maximum height v = 0, vo -gt = 0 and

T = vo / g = 20 m/s / 9.81 m/s² = 2.04 s

Now height y = vot -0.5 gt^2 = 20,4 m

This is possible to solve using

Conservation of energy Ek= Ep

0.5mv² = mgh. And h = v²/2g. Results same

33: i think it’s b