The rod connected halfway along the 0.660 m radius of a wheel exerts a 2.27 × 10^5 N force. How large is the maximum torque?

1.498×10⁵ Nm

Explanation:

From the question above,

Torque (T) = Force (F) × radius (r)

T = F×r Equation 1

Where T = Torque, F = force, r = radius .

Given: F = 2.27×10⁵ N, r = 0.660 m

Substitute these values into equation 1

T = 2.27×10⁵×0.660

T  = 1.498×10⁵ Nm

Hence the torque of the wheel is 1.498×10⁵ Nm

attach the statements so i can answer : )

answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg