The specific heat of water in its solid phase (ice) is 2090 J/(kg K), while in the liquid phase (water) its specific heat is 4190 J/(kg K). Water's latent heat of fusion is 333,000 J/kg. If you have a 2kg block of ice at -90°C and you add 1,000,000 J of heat, what is its new temperature? a. 0°C
b. 14°C
c. 49°C
d. 149°C

d. 149 ⁰C.

Explanation:

Given;

mass of the block of ice, m = 2 kg

specific heat capacity of the ice, C = 2090 J/(kgK)

initial temperature of the ice, t₁ = -90 ⁰C

heat added to the ice, H = 1,000,000 J

let the final temperature of the ice = t₂

The final temperature of the ice after adding the heat is calculated as follows;

Therefore, the new temperature of the water is 149 ⁰C.

i don't understand. explain it clearly