Oints) Two ropes are attached to a wagon, one horizontal to the west with a tension force of 30 N
and the other east and at an angle of 30° northward and a tension force of 40 N. Find the
components of the net force on the cart. Show all your work.

Assuming the two ropes are knotted onto the same point of the wagon, the net force is computed of the sum of the two stated.The westward force is Fw = (-30,0); then the northeastward force is Fne = (50*cos(30°),50*sin(30°)).Adding the two is just adding each part, so the resulting force is Fnet = (-30+50*cos(30°),50*sin(30°)).  

Going more than that, the magnitude uses the Pythagorean formula:so √[(-30+50*cos(30°))²+(50*sin(30°))²] which is about 28.32N.  

Explanation: jus understanddd myy ansswerr hehezz

that would be because of both gravity and friction. so     c

if the person is shown to have +90n, then ans is -10n.

if the person is shown to have -90n, then ans is +10n.