PLEASE HELP PHYSICS Wiley coyote pushes a 5kg boulder from an initial height of 10m, the boulder rolls down the hill, across the road, and up the hill on the left. The rock is able to reach a height of 17 m before rolling back down. How fast did Wiley have to push the rock to make this happen?

  v = 11.7 m / s

Explanation:

For this exercise we can use the conservation of energy

starting point. Where you drop the stone

          Em₀ = K + U = ½ m v² + m g h₁

final point. Point where the stone arrives

          Em_f = U = mgh₂

We are assuming that there is no friction, so the energy is conserved

          Em₀ = Em_f

          ½ m v² + m g h₁ = m g h₂

         v² = 2g (h₂-h₁)

let's calculate

         v² = 2 9.8 (17 - 10)

         v = √137.2

         v = 11.7 m / s

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