Un hombre camina 400m hacia el oeste luego 200m hacia el norte. Determina la magnitud y la dirección del desplazamiento resultante

d = 447.21 m,   θ = 153.4º

Explanation:

Let's use the Pythagoras network theorem to find the magnitude of the displacement

          d =

          d =

          d = 447.21 m

To encode the direction, let's use trigonometry, we take the East and North directions as positive.

          tan θ’= y / x

          θ'= tan⁻¹ y / x

          θ'= tan⁻¹ (200/400)

          θ ’= 26.6º

This angle is in the second quadrant, so measured from the positive side of the x-axis (East direction)

          θ = 180 - θ'

          θ = 180 -26.6

          θ = 153.4º

d.7.5cm is your answer