A block of metal of density 3000 kg/m3 is 2m high and stands on a square base of side 0.5 m. Calculate: 1.The area of the base of the block
2.The volume of the block
3.Mass of the block
4.Weight of the block
5.The pressure exerted by the block

1)  A = 0.25 m², 2) V = 0.5 m³, 3)   m = 1500 kg, 4) W = 14700 N,

5)  P = 58800 Pa

Explanation:

1) The area of ​​the base is square

          A = L²

         A = 0.5²

         A = 0.25 m²

2) The block is a parallelepiped

         V = A h

         V = 0.25 2

          V = 0.5 m³

3) Density is defined

           rho = m / V

           m = rho V

           m = 3000 0.5

           m = 1500 kg

4) The weight of a body is

           W = mg

            W = 1500 9.8

            W = 14700 N

5) The pressure is

             P = F / A

in this case the force is equal to the weight of the body

              P = 14700 / 0.25

              P = 58800 Pa

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