After interference, the two waves that were interacting A. continue with a different wavelength than before
B. continue with a different amplitude than before
C. continue with a different speed than before
D. no longer exist
E. continue unchanged by the interaction

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer

i believe the answer is a hope it and is correct

distance = 150m

displ = root (50 ^2 + 100^2)

root(2500+10000)

root 125000

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j