A200 g puck revolves in a circle on a frictionless table at the end of a 50.0 cm long string. the puck's angular momentum is 3.00 kg⋅m2/s. what is the tension in the string

The tension in the string holding the  puck is .

Further Explanation:

Given:

The mass of the puck is or .

The length of the string or the radius of the circular path is or .

The angular momentum of the rotating puck is .

Concept:

As the puck revolves in a circle on the frictionless table, the puck experiences an outward centripetal force and this force is equal to the tension developed in the string holding the puck.

The angular momentum of the puck can be expressed as:

Substitute the value of , and  in above expression.

Now, the centripetal force acting on the puck is balanced by the tension developed in the string.

Use the force balancing equation for the puck.

Substitute the values of , and in above expression.

Thus, the tension in the string holding the puck is  .

Learn More:

1. Mass m, moving at speed 2v, approaches mass 4m, moving at speed v. The two collide elastically head-on

2. A basketball player can jump vertically 0.9 m. Assume that the jump interval

3. For inelastic collisions which of the following statements can be true

Answer Details:

Grade: College

Subject: Physics

Chapter: Angular Momentum

Keywords:  200g puck, frictionless table, 50 cm long string, angular momentum, tension, L=mvr, centripetal force, mv^2/r, revolves in a circle, tension developed.

+15-35=-20

going in opposite directions

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