5. An electron is separated from a proton by a distance of 1.00 10^-10 m. What is the magnitude of the electric force between them?​

2.304 * 10^-10N

Explanation:

The magnitude of the force is expressed as;

F = kq1q2/r²

k is the coulomb constant

q1 id the charge on the electron = -1.6*10^-19C

q2 is the charge on the proton = 1.6*10^-19C

k = 9*10^9

Substitute

F  = (9*10^9)*( -1.6*10^-19)( 1.6*10^-19)/(1.00 10^-10)^2

F = 9*10^9*-2.56*10^-38/1.00 10^-20

F = -23.04*10^-29/1.00 10^-20

F = -23.04 * 10^(-29+20)

F = -23.04 * 10 ^-9

F = -2.304 * 10 ^ -10N

Hence the magnitude of the electric force between them is

2.304 * 10^-10N

answer: the exterior temperature of commercial jet planes as they leave the stratosphere and return to the ground increases steadily.

explanation:

the lower most layer of atmosphere is troposphere which extends from 0 to 12 km above the surface of the earth. the temperature initially decreases as distance is increased from the earth's surface. commercial jets fly in lower part of the stratosphere. the stratosphere extends upto 50 km. the temperature in stratosphere starts rising again due to presence of ozone which traps the uv rays.

thus, when the planes leave the stratosphere and return to the ground, the exterior temperature increases steadily.

layers of the earth affect the waves and these effects are seen on instruiments such as seimometers