While watching a small fireworks display from a building 204 feet tall, you observe a rocket that travels from ground to eye level in 6 seconds, and explodes. what is the maximum speed that you can guarantee that the rocket reached?

204 ft = 62.2 m
We know that the initial velocity of the rocket was 0, we can find its acceleration using:
s = ut + 1/2 at²
62.2 = 0.5a(6)²
a = 3.46 m/s²
Now, the final velocity of the rocket:
v = u + at
v = 3.46 x 6
v = 20.76 m/s = 68.1 ft/s

What are you trying to ask?