First timer ..
sharon is jumping from an 18-foot diving board with an initial upward velocity of 4 ft/s. when susan jumps, megan throws a beach ball up to susan with an initial upward velocity of 16 ft/s from a height 5 feet off the ground. to the nearest hundredth of a second, how long after she jumps does the ball reach sharon?
0.65 seconds
0.92 seconds
1.08 seconds
1.15 seconds

Answer : t = 1.08 seconds

Explanation :

Let be the height of Sharon from ground,

be the height of Megan from ground,

Initial upward velocity of Sharon,

Initial upward velocity of Megan,

Let h (t) is the height from ground when the ball reaches Sharon.

using the equation of motion as

Similarly,

Equating equations (1) and (2)

The ball will reach after 1.08 seconds.

So, correct option is (c)