WAEC 1989 A 117200 65. An electric heater immersed in some water raises the temperature of the water
from 40°C to 100°C in 6 minutes. After another 25 minutes, it is noticed that half the
water has boiled away. Neglecting heat losses to surrounding, calculate the specific latent
heat of vapourization of water.

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The rocks expand when there hot/warm  and contract when they are cold.

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

A,d, and e on edgunuity

Idon't know the answer google it