3. A record 0.30 cm in diameter rotates 33.5 times per minute. a. What is its frequency?

b. What is its period?

c. What is the linear speed of a point on its rim?

d. What is the centripetal acceleration of a point on its rim?

Explanation:

The diameter of a record, d = 0.3 cm

Radius, r = 0.15 cm

It rotates 33.5 times per minute.

(a) Frequency, f = 33.5 rotation/minute

= (33.5/60) rotation/second

= 0.55 rotation/second

(b) Time period,

T = 1/f

So,

(c) Linear speed of a point on its rim,

(d) Centripetal acceleration,

Hence, this is the required solution.

gravity

explanation:

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.