What is the magnitude of the electric field strength between them, if the potential 7.05 cm from the zero volt plate (and 2.95 cm from the other) is 293 V?

E = 4156.02 Vm⁻¹

Explanation:

The magnitude of the uniform electric field between the plates can be given by the following formula:

where,

E = Electric field strength = ?

ΔV = Potetial Difference = 293 V

d = distance between plates = 7.05 cm = 0.0705 m

Therefore,

E = 4156.02 Vm⁻¹

not too sure thinking all accelerations are pointed down

prndulum needs thread, weight clock to time swings