To what temperature will a 50.0 g piece of glass raise if it absorbs 5275 joules of heat and its specific heat capacity is 0.50 J/g°C? The initial temperature of the glass is 20.0°C.

Final temperature, T2 = 131895°C

Explanation:

Given the following data;

Mass = 50g

Initial temperature = 20°C

Quantity of heat = 5275J

Specific heat capacity = 0.50 J/g°C

To find the final temperature;

Heat capacity is given by the formula;

Where;

Q represents the heat capacity or quantity of heat.

m represents the mass of an object.

c represents the specific heat capacity of water.

dt represents the change in temperature.

Making dt the subject of formula, we have;

Substituting into the equation, we have;

dt = 131875°C

Now, the final temperature T2 is;

But, dt = T2 - T1

T2 = dt + T1

T2 = 131875 + 20

T2 = 131895°C

answer: option c. i.e. electric current flowing “downhill” from the negative electrode to the positive electrode in a battery

explanation:

the water analogy to the circuits define the pipes (water flows) to the electric current. now, we know that the electric current flows from the positive terminal to the circuit (as shown in the diagram attached).

hence, option c is the correct answer.

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