A 743 kg car moving at 12.0 m/s hits from behind another car moving at 11.1 m/s in the same direction. If the second car has a mass of 600 kg and a new speed of 14.8 m/s, what is the velocity of the first car after
the collision?

The answer to your is is c motion and shape

Domain eukarya; kingdom plantae should be the answer.

Iwould have to say sorry i can't elaborate more. hope this though!

Since you have not included the experiment situation and the data, of course, i can not give you specific details about it. but i can you with this question.1) i will assume that the motion is projectile (parabolic) motion.2) yes, the horizontal distance depends on the horizontal velocity as, naming vx the horizontal velocity and t the time, it is: x = vx × t3) now, observe that the flight time depends on the vertical velocity as, naming voy the initial vertical velocity, t the time and y the vertical distance before reaching the ground: y = yo + voy×t - gt² / 2.the higher the initial vertical velocity (voy) the longer the object will be flying and so t will be higher in the equation for the horizontal distance.that explains the relationship between the horizontal distance and the horizontal velocity.