A charge of 0.50 C moves horizontally in a magnetic field of 1.0 T with a speed of 4.0 x 10^2 m/s. The force experienced by the charge is 7.0 N. What is the angle between the charge direction and the magnetic field?​

Question: A charge of 0.50 C moves horizontally in a magnetic field of 1.0 T with a speed of 4.0 x 10^⁻1 m/s. The force experienced by the charge is 7.0 N. What is the angle between the charge direction and the magnetic field?​

Θ = 6.56°

Explanation:

From the question,

Using

F = BvqsinΘ Equation 1

Where F = force experienced by the charge, B = magnetic field, q = Charge, Θ = angle between the charge abd the magnetic field, v = velocity.

Make Θ the subject of the equation

Θ =sin⁻¹ (Bvq/F) Equation 2

Given: v = 4.0×10⁻¹ m/s, B = 1.0 T, q = 0.50 C, F = 7.0 N

Θ = sin⁻¹(1×0.5×4×10⁻¹/7)

Θ = sin⁻¹(0.114)

Θ = 6.56°

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases . this process does not change the mass number.

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as -decay. in this the mass number remains same.

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.

f=ma a/f/m a= 480/60 a = 8m/s/s that is quick wow