Physics, 26.02.2021 06:00 bryan519688

A 0.150 kg cube of ice (frozen water) is floating in glycerin. The glycerin is in a tall cylinder that has inside radius 5.50 cm. The level of the glycerin is well below the top of the cylinder. Part A If the ice completely melts, by what distance does the height of liquid in the cylinder change

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Answer from: clwalling04

The question is incomplete. Here is the complete question.

A 0.150 kg cube fo ice (frozen water) is floating in glycerine. The glycerine is in a tall cylinder that has inside radius 3.10 cm. The level of the glycerine is well below the top of the cylinder.

Part A

If the ice completely melts, by what distance does the height of liquid in the cylinder change? Express your answer with the appropriate units.

Part B

Does the level of liquid rise or fall? That is, is the surface of the water above or below the original level of the glycerine before the ice melted?

Part A: $\Delta h=$ 327 mm

Part B: Rise

Explanation: When an object is submerged on a fluid, the fluid exerts a upward force on the object called Buoyant Force. It can be calculated by the following relation:

$B=\rho_{fluid}gV$

Part A

Because the ice cube is floating on glycerin, its forces are on equilibrium, which means buoyant and weight are equal:

$\rho_{fluid}gV=mg$

Density of glycerine is 1260 kg/m³.

Volume of a cylinder is $V=\pi.r^{2}.h$

Solving

$\rho_{fluid}gV=mg$

$\rho_{g}.V=m$

$\rho_{g}.\pi.r^{2}.h_{1}=m$

$h_{1}=\frac{m}{\rho_{g}.\pi.r^{2}}$

$h_{1}=\frac{0.15}{1260.\pi.(0.055)^{2}}$

$h_{1}=1.25$ m

After melted, the volume of a mass of water created is

$\rho_{w}=\frac{m}{V}$

$V=\frac{m}{\rho_{w}}$

Density of water is 10³ kg/m³.

$\pi.r^{2}.h_{2}=\frac{m}{\rho_{w}}$

$h_{2}=\frac{m}{\rho_{w}.\pi.r^{2}}$

$h_{2}=\frac{0.15}{1000.(0.055)^{2}.\pi}$

$h_{2}=$ 1.58 m

The change in heights is

$\Delta h=h_{2}-h_{1}$

$\Delta h=$ 0.327 m

The distance by which the height of liquid in the cylinder change is 327mm.

Part B:

Water has more density than ice. So, when melted, water will take the place of glycerin more than ice and so, liquid will rise on the cylinder.

Answer from: Quest

explanation:

v=uf/(u-f)

= 5.-10/(5+10) convex lens has negative focal length

An object is located 5.0 cm from a convex lens. the lens focuses light at a distance of 10.0 cm. wha

Answer from: Quest

answer

procedural programming, object-oriented programming

explanation

procedural programming is a type of computer programming language that specifies a series of well structured steps and procedures within its development period of time. it contains a systematic order of statements, functions and commands to complete a computational task or program. it is centered on creating procedures. while object oriented programming is a programming language that is centered on creating objects rather that actions and data rather than logic.. it has four principles which are inheritance, polymorphism, abstraction and encapsulation

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A 0.150 kg cube of ice (frozen water) is floating in glycerin. The glycerin is in a tall cylinder th...

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